Input parameters

Verbal explanation
Phase 1 - cylinder pressures
- Cylinder loads are known
- Cylinder piston (A) areas can be calculated
- No (gauge) pressure in the B chamber, no hydraulic load
- No friction
- The cylinder pressures 1 and 2 can be calculated
Phase 2 - cylinder 1 flow rate
- Cylinder piston 1 velocity is known
- Piston area (1) is known, no leakage
- The flow rate (1) can be calculated
Phase 3 - orifice 1 pressure drop
- Orifice flow areas 1 and 2 (the same) can be calculated
- Pressure drop (Pump->1) can be calculated (Flow rate is known)
Phase 4 - pump pressure
- Cylinder 1 pressure and pressure drop (Pump -> 1) are known
- Pump pressure is the sum of these pressures
Phase 5 - cylinder 2 flow rate and velocity
- Cylinder pressure 2 and pump pressure are known
- Pressure drop over orifice 2 can be calculated
- Flow rate through orifice 2 can be calculated
- No leakage in cylinder
- Lifting velocity of cylinder piston 2 can be calculated
Phase 6 - pump power
- Pump flow rate is the sum of cylinder flow rates (1 and 2)
- Pump power can be calculated, pressure and flow rate are known

Solution

Results