MS-A0211 - Differential and Integral Calculus 2, Lecture, 10.1.2023-20.2.2023
This course space end date is set to 20.02.2023 Search Courses: MS-A0211
Lecture 7 - 31.1.2023
Completion requirements
In this lecture we studied:
- Absolute extreme values (min/max). We stated the theorem that continuous functions of two variables defined on closed and bounded regions attain their absolute extrema. How to find the absolute extrema on a closed and bounded domain D? Step 1. Find critical and singular points on the interior of D (as we know from the previous lecture). Step 2. Find any point on the boundary of D where f might have extreme values. Step 3. Evaluate f at all the points found in steps 1 and 2. We found the absolute extrema of f(x,y) = x^2 + 2 y^2 on the disk of radius one centered at (0,0). For that, on the boundary (step 2) we reduced the problem to a one variable problem.
- Method of Lagrange multipliers. We discussed the method of Lagrange multipliers and justified it intuitively by looking at a sketch of level curves and using the fact that the gradient vectors are orthogonal to the corresponding level curves. We noticed that the absolute extrema of f(x,y) subject to g(x,y)=c can occur at points where the gradient of f is parallel to the gradient of g (Lagrange multipliers) or at points where the gradient of f is not defined. We re-solved step 2 of the previous example by using the method of Lagrange multipliers. We did another example of Lagrange multipliers: on the curve x^2 + xy+y^2=1 which points are closest and furthest from the origin?